(8x+3)/4x+2(x-3)^2/8-6x/2+4/2+1/4=(x-2)^2/4

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Solution for (8x+3)/4x+2(x-3)^2/8-6x/2+4/2+1/4=(x-2)^2/4 equation:


x in (-oo:+oo)

x*((8*x+3)/4)+(2*(x-3)^2)/8-((6*x)/2)+4/2+1/4 = ((x-2)^2)/4 // - ((x-2)^2)/4

x*((8*x+3)/4)+(2*(x-3)^2)/8-(((x-2)^2)/4)-((6*x)/2)+4/2+1/4 = 0

x*((8*x+3)/4)+(2*(x-3)^2)/8-(((x-2)^2)/4)-3*x+4/2+1/4 = 0

(x*(8*x+3))/4+(2*(x-3)^2)/8+(-1*(x-2)^2)/4-3*x+1/4+2 = 0

(8*x*(8*x+3))/(4*8)+(2*4*(x-3)^2)/(4*8)+(-1*8*(x-2)^2)/(4*8)+(-3*4*8*x)/(4*8)+(2*4*8)/(4*8)+(1*8)/(4*8) = 0

8*x*(8*x+3)+2*4*(x-3)^2-1*8*(x-2)^2-3*4*8*x+2*4*8+1*8 = 0

72*x^2-8*x^2-24*x+32*x-96*x-32+8+64+72 = 0

64*x^2+8*x-96*x+8+40+64 = 0

64*x^2-88*x+8+40+64 = 0

64*x^2-88*x+8+104 = 0

64*x^2-88*x+112 = 0

64*x^2-88*x+112 = 0

8*(8*x^2-11*x+14) = 0

8*x^2-11*x+14 = 0

DELTA = (-11)^2-(4*8*14)

DELTA = -327

DELTA < 0

8 = 0

8/(4*8) = 0

8/(4*8) = 0 // * 4*8

8 = 0

x belongs to the empty set

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